#include <iostream>
#include <string>
#include <vector>
#include "Graph.h"
#include "Edge.h"
#include "Tree.h"
using namespace std;
int main()
{
string vertices[] = {"Seattle", "San Francisco", "Los Angeles",
"Denver", "Kansas City", "Chicago", "Boston", "New York",
"Atlanta", "Miami", "Dallas", "Houston"};
int edges[][2] = {
{0, 1}, {0, 3}, {0, 5},
{1, 0}, {1, 2}, {1, 3},
{2, 1}, {2, 3}, {2, 4}, {2, 10},
{3, 0}, {3, 1}, {3, 2}, {3, 4}, {3, 5},
{4, 2}, {4, 3}, {4, 5}, {4, 7}, {4, 8}, {4, 10},
{5, 0}, {5, 3}, {5, 4}, {5, 6}, {5, 7},
{6, 5}, {6, 7},
{7, 4}, {7, 5}, {7, 6}, {7, 8},
{8, 4}, {8, 7}, {8, 9}, {8, 10}, {8, 11},
{9, 8}, {9, 11},
{10, 2}, {10, 4}, {10, 8}, {10, 11},
{11, 8}, {11, 9}, {11, 10}
};
const int NUMBER_OF_EDGES = 46;
vector<string> vectorOfVertices(12);
copy(vertices, vertices + 12, vectorOfVertices.begin());
Graph<string> graph(vectorOfVertices, edges, NUMBER_OF_EDGES);
Tree dfs = graph.dfs(5);
vector<int> searchOrders = dfs.getSearchOrders();
cout << dfs.getNumberOfVerticesFound() <<
" vertices are searched in this DFS order:" << endl;
for (unsigned i = 0; i < searchOrders.size(); i++)
cout << graph.getVertex(searchOrders[i]) << " ";
cout << endl << endl;
for (unsigned i = 0; i < searchOrders.size(); i++)
if (dfs.getParent(i) != -1)
cout << "parent of " << graph.getVertex(i) <<
" is " << graph.getVertex(dfs.getParent(i)) << endl;
return 0;
}